How do I name this? 1-bromo-2-isobutyl-4-???
By - monopamiaG
it’s 4-bromo-3-isobutyl benzoic acid
Acid gets priority
If you have chemdraw downloaded you can have it name it for you.
I may be wrong on the numbering, but I believe it’s 4-bromo-5-isobutyl benzoic acid
It was 4-bromo-3-isobutylbenzoic acid but I don’t understand why it’s 3-isobutyl and not 5. Because aren’t the double bonds supposed to be coupled forcing the locator number to go counterclockwise?
you want all the numbers to be as small as possible
So compared with straight chain alkene naming, we ignore the rule that the double bonds must be counted together in rings?
I think the benzene ring is counted as a single unit
Yeah whatever substituent is closest to the carb. acid gets the first numbering
All benzene carbons without substituents are equivalent. Starting from the COOH, if the isobutyl group wasn't there, it wouldn't matter if you count clockwise or counter clockwise to get to Br.
Since the isobutyl group is there, now you have to count counter clockwise to give every substituent the lowest number possible.
In a benzene ring the double bonds go back in forth that is why it is sometimes shown as a hexagon with a circle inside
Resonance. Hybrid structure. The bonds are not fixed to specific C's
Remember benzene doesn’t really have double bonds
You always give substituents the lowest number you can I'm pretty sure. If you have a 5 and 3 position you prioritize by alphabetical order I think (I don't remember iupac very well).
parent chain numbering is always the lowest in all iupac naming
4 bromine 3 isobutyl benzoic acid
Bro are we just helping ppl cheat on tests now?
just to be safe, I only answer questions after minimum 1h... and it's entertaining to solve org chem question
I think an automatic delay of about 1-2 hours before the post is shown to the public would be good to avoid this problem. I don't know if it is automatizable.
I'm sure someone could set up a bot to do it, but unless they wanted to hold *all* posts for 1 hour, and then show them to the public, I think it would have to be a pretty complex bot.
It would have to be able to tell "is this a test question or not?" which, don't get me wrong, *is* doable; but I have a suspicion that would be complicated. Think "learning algorithm" complicated. Maybe there is something on github for it already though, so it might not be too difficult. I might look into this later, and let the mods know if I find anything.
RemindMe! 4 hours
I think that holding all posts for 1 or 2 hours won't be a problem at all, since usually the posts I see in this sub aren't answered until a few hours later.
I will be messaging you in 4 hours on [**2021-10-14 16:36:26 UTC**](http://www.wolframalpha.com/input/?i=2021-10-14%2016:36:26%20UTC%20To%20Local%20Time) to remind you of [**this link**](https://www.reddit.com/r/OrganicChemistry/comments/q7qtf4/how_do_i_name_this_1bromo2isobutyl4/hglr71q/?context=3)
[**CLICK THIS LINK**](https://www.reddit.com/message/compose/?to=RemindMeBot&subject=Reminder&message=%5Bhttps%3A%2F%2Fwww.reddit.com%2Fr%2FOrganicChemistry%2Fcomments%2Fq7qtf4%2Fhow_do_i_name_this_1bromo2isobutyl4%2Fhglr71q%2F%5D%0A%0ARemindMe%21%202021-10-14%2016%3A36%3A26%20UTC) to send a PM to also be reminded and to reduce spam.
^(Parent commenter can ) [^(delete this message to hide from others.)](https://www.reddit.com/message/compose/?to=RemindMeBot&subject=Delete%20Comment&message=Delete%21%20q7qtf4)
this is on smartwork5, its for homework.
Sadly that is what this sub reddit is most used for. Or helping with studying.
I mean it helped me understand and I'm not taking a test. It could just be helping them with their homework also.
Where does the 3 part come from, is it because the butyl group is on the third carbon chain? I originally thought the number would be 5 because the carbon chain is on the 5th carbon of the benzene ring.
What a ridiculous question.... This is a pointless exercise you are being set because it's easy to set this sort of work rather than learning something meaningful.
I’m only in ochem 1, but what makes you think learning nomenclature is pointless?
A meaningful task would be about the synthesis of these molecules, not naming them.
Some nomenclature is completely necessary, but the compound you linked is well over that line.
I think it's a good question to distinguish priority. Nomenclature is common place in early undergraduate studies (I also did undergraduate and masters in UK university). It's normally a good set up for when chirality and other isomeric features are taught.
Learning to that level is useless. I completed a UK masters in chem at the rank #1 uni. We didn't do any nomenclature to this level. We were given a copy of chem draw and shown how to use the name function.
Wow.. you are quite the office tart
I'm assuming OP didn't find it trivial or they wouldn't have posted it. And actually reading the comments it seems they have learnt from this post. That's what this community is for if I'm not wrong.
Well actually calling it a community is a contradiction by you and based on your previous comments you seem to enjoy belittling others for your own benefit. It doesn't make you a better chemist to accuse those below you of laziness or trivializing what they find difficult.
I agree sometimes the questions and topics here are interesting and thought-provoking and some not. But again that's what the community is about.
Sincerely a chemist who has experienced a lot of other chemists trying to belittle others to make themselves seem smarter.
And I didn't want to turn this into a pissing contest but that's clearly what you're doing, I think my h-index would suggest I'm not lazy.
Best of luck
Well I bet you're fun at parties...
How about you just don't comment and focus on the stuff that matches your superior intellect.
Good luck teaching, maybe don't take this approach toward your students, for their sake
Lol you’re hilarious and I truly wish to avoid people like you in the real world! Cheers.
Halt die Klappe du fette Schlampe
My thoughts exactly
You can just say you don’t know the answer and move along.